An economist wants to compare the average hourly rate charged by automobile mechanics in two suburbs. She randomly selects auto repair facilities from both suburbs and records their hourly rates (in dollars). The data are as follows:
Suburb 1:
40.4 | 41.8 | 40.1 | 41.1 | 44.5 |
40.8 | 32.2 | 49.2 | 47.6 | 35.8 |
40.8 | 38 | 40.7 | 48.9 | 37.8 |
44.1 | 48.8 | 30.9 | 40.7 | 42.4 |
(Note: The average and the standard deviation of the data are respectively 41.3 $ and 5.04 $.)
Suburb 2:
47.2 | 43.2 | 51.4 | 40.9 | 44.2 |
43.4 | 48.5 | 51 | 38.3 | 30 |
39.7 | 44.3 | 49.9 | 43.3 | 44 |
(Note: The average and the standard deviation of the data are respectively 44 $ and 5.52 $.)
Use 5% level of significance to decide whether there is a sufficient evidence that the average hourly rate charged by automobile mechanics in suburb 1 is less than the average hourly rate charged by automobile mechanics in suburb 2.
Hint: The standard deviation for the first sample appears to be different from the standard deviation of the second sample. To check this claim the two-tail F-test for two variances can be setup which will result in the p-value of 0.699. Use the significance level of 5% to interpret this as sufficient or insufficient evidence that the two populations have different standard deviations and then decide whether to use the pooled or non-pooled procedure.
Procedure:
Assumptions: (select everything that applies)
Step 1. Hypotheses Set-Up:
= | , where the and the units are |
, and the test is |
Step 2. The significance level %
Step 3. Compute the value of the test statistic: = (Round the answer to 3 decimal places)
Step 4. Testing Procedure: (Round the answers to 3 decimal places)
CVA | PVA |
Provide the critical value(s) for the Rejection Region: | Compute the P-value of the test statistic: |
left CV is and right CV is | P-value is |
Step 5. Decision:
CVA | PVA |
Is the test statistic in the rejection region? | Is the P-value less than the significance level? |
Conclusion:
Step 6. Interpretation:
At 5% significance level we have sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.
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