Solve the following system of equations with the substitution method:

{x=4y+73x+y=8\displaystyle {\left\lbrace\begin{array}{ccc} {x}&=&-{4}{y}+{7}\\-{3}{x}+{y}&=&-{8}\end{array}\right.}

Answer: (x,y)=\displaystyle {\left({x},{y}\right)}= (,)
Preview x\displaystyle {x}:  
Preview y\displaystyle {y}:  


Enter your answers as integers or as reduced fractions in the form A/B.