Suppose f(x)=2x2+7x+6\displaystyle {f{{\left({x}\right)}}}={2}{x}^{{2}}+{7}{x}+{6}. Compute the following:

f(3)=\displaystyle {f{{\left(-{3}\right)}}}=

f(1)=\displaystyle {f{{\left({1}\right)}}}=