The currents (measured in amperes) running through an electrical system are given by the following system of equations. Solve the system to find the currents in this circuit.


{5I1−5I2−9I3=48−2I1+4I2+6I3=−28I1−I2−3I3=12\displaystyle {\left\lbrace\begin{array}{ccccccc} {5}{I}_{{1}}&-&{5}{I}_{{2}}&-&{9}{I}_{{3}}&=&{48}\\-{2}{I}_{{1}}&+&{4}{I}_{{2}}&+&{6}{I}_{{3}}&=&-{28}\\{I}_{{1}}&-&{I}_{{2}}&-&{3}{I}_{{3}}&=&{12}\end{array}\right.} 


x =  
y =  
z =  

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