The currents (measured in amperes) running through an electrical system are given by the following system of equations. Solve the system to find the currents in this circuit.


{2I1−2I2−6I3=−12−8I1+7I2+6I3=94I1−4I2−3I3=−6\displaystyle {\left\lbrace\begin{array}{ccccccc} {2}{I}_{{1}}&-&{2}{I}_{{2}}&-&{6}{I}_{{3}}&=&-{12}\\-{8}{I}_{{1}}&+&{7}{I}_{{2}}&+&{6}{I}_{{3}}&=&{9}\\{4}{I}_{{1}}&-&{4}{I}_{{2}}&-&{3}{I}_{{3}}&=&-{6}\end{array}\right.} 


x =  
y =  
z =  

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