The following inequality has a solution in the form x≥A.\displaystyle {x}\ge{A}.x≥A. Solve the inequality and place the correct value of A\displaystyle {A}A into the box.−8x−7≤−4+13x\displaystyle -{8}{x}-{7}\le-{4}+{13}{x}−8x−7≤−4+13x Answer: x≥\displaystyle {x}\gex≥ Enter your answer as an integer or a reduced fraction in the form A/B. Preview Question 6
Submit Try a similar question