The following inequality has a solution in the form $\displaystyle {x}\le{A}.$ Solve the inequality and place the correct value of $\displaystyle {A}$ into the box.

$\displaystyle {11}{x}-{15}\le{5}+{3}{x}$

Answer: $\displaystyle {x}\le$   Enter your answer as an integer or a reduced fraction in the form A/B.
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