The following inequality has a solution in the form x≥A.\displaystyle {x}\ge{A}.x≥A. Solve the inequality and place the correct value of A\displaystyle {A}A into the box.−2x+10≤−9+13x\displaystyle -{2}{x}+{10}\le-{9}+{13}{x}−2x+10≤−9+13x Answer: x≥\displaystyle {x}\gex≥ Enter your answer as an integer or a reduced fraction in the form A/B. Preview Question 6
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