The following inequality has a solution in the form x≤A.\displaystyle {x}\le{A}.x≤A. Solve the inequality and place the correct value of A\displaystyle {A}A into the box.16x+2≤−13+9x\displaystyle {16}{x}+{2}\le-{13}+{9}{x}16x+2≤−13+9x Answer: x≤\displaystyle {x}\lex≤ Enter your answer as an integer or a reduced fraction in the form A/B. Preview Question 6
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