The following inequality has a solution in the form xA.\displaystyle {x}\le{A}. Solve the inequality and place the correct value of A\displaystyle {A} into the box.

16x+213+9x\displaystyle {16}{x}+{2}\le-{13}+{9}{x}

Answer: x\displaystyle {x}\le
Enter your answer as an integer or a reduced fraction in the form A/B.