For a uniform random variable U∼U(4,24)\displaystyle {U}\sim{U}{\left({4},{24}\right)}U∼U(4,24), find the probability P(U>13)\displaystyle {P}{\left({U}>{13}\right)}P(U>13):
P(U>13)=\displaystyle {P}{\left({U}>{13}\right)}=P(U>13)= (Round the answer to 4 decimal places)
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