Find
∫
9
sin
(
3
x
)
d
x
\displaystyle \int{9}{\sin{{\left({3}{x}\right)}}}{\left.{d}{x}\right.}
∫
9
sin
(
3
x
)
d
x
∫
9
sin
(
3
x
)
d
x
=
\displaystyle \int{9}{\sin{{\left({3}{x}\right)}}}{\left.{d}{x}\right.}=
∫
9
sin
(
3
x
)
d
x
=
Preview
Question 6
+
C
\displaystyle +{C}
+
C
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