Multiply and simplify:
2
x
3
y
3
15
x
2
y
6
⋅
4
x
2
y
3
9
x
4
y
5
\displaystyle {2}{x}^{{3}}{y}^{{3}}\sqrt{{{15}{x}^{{2}}{y}^{{6}}}}\cdot{4}{x}^{{2}}{y}^{{3}}\sqrt{{{9}{x}^{{4}}{y}^{{5}}}}
2
x
3
y
3
15
x
2
y
6
⋅
4
x
2
y
3
9
x
4
y
5
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Question 6
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