Solve the formula for
y
\displaystyle {y}
y
6
y
+
y
p
p
=
d
\displaystyle \frac{{{6}{y}+{y}{p}}}{{{p}}}={d}
p
6
y
+
y
p
=
d
y
=
\displaystyle {y}=
y
=
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Question 6
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