Use the properties of exponents to simplify the following. Be sure that your final answer has only one of each base and is expressed using only positive exponents. 

 [(d1g3)5÷(d5g6)4]2=\displaystyle {\left[{\left(\frac{{d}^{{-{{1}}}}}{{g}^{{-{{3}}}}}\right)}^{{-{{5}}}}\div{\left(\frac{{d}^{{-{{5}}}}}{{g}^{{-{{6}}}}}\right)}^{{-{{4}}}}\right]}^{{-{{2}}}}=