Find the
4
t
h
\displaystyle {4}^{{{t}{h}}}
4
t
h
term of the recursive sequence
{
a
1
=
11
a
n
=
17
(
a
n
−
1
+
4
)
\displaystyle {\left\lbrace\begin{array}{c} {a}_{{1}}={11}\\{a}_{{n}}={17}{\left({a}_{{{n}-{1}}}+{4}\right)}\end{array}\right.}
{
a
1
=
11
a
n
=
17
(
a
n
−
1
+
4
)
a
4
=
\displaystyle {a}_{{4}}=
a
4
=
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