Find the first derivative of
g
(
t
)
=
ln
(
e
t
t
6
)
\displaystyle {g{{\left({t}\right)}}}={\ln{{\left(\frac{{e}^{{t}}}{{t}^{{6}}}\right)}}}
g
(
t
)
=
ln
(
t
6
e
t
)
.
g
′
(
t
)
=
\displaystyle {g}'{\left({t}\right)}=
g
′
(
t
)
=
Preview
Question 6
Submit
Try a similar question
License
[more..]
\displaystyle
Enter your answer as an expression. Example: 3x^2+1, x/5, (a+b)/c
Be sure your variables match those in the question