Solve the Cauchy-Euler equation
t
2
y
′
′
−
10
t
y
′
+
28
y
=
0
\displaystyle {t}^{{2}}{y}{''}-{10}{t}{y}'+{28}{y}={0}
t
2
y
′′
−
10
t
y
′
+
28
y
=
0
with initial conditions
y
(
1
)
=
−
2
,
y
′
(
1
)
=
7
\displaystyle {y}{\left({1}\right)}=-{2},{y}'{\left({1}\right)}={7}
y
(
1
)
=
−
2
,
y
′
(
1
)
=
7
.
y
(
t
)
=
\displaystyle {y}{\left({t}\right)}=
y
(
t
)
=
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