Determine if the series converges or diverges.
∑
n
=
1
∞
1
n
6
+
8
2
\displaystyle {\sum_{{{n}={1}}}^{\infty}}\frac{{1}}{{{\sqrt[{{2}}]{{{n}^{{{6}}}+{8}}}}}}
n
=
1
∑
∞
2
n
6
+
8
1
Converges
Diverges
Submit
Try a similar question
License
[more..]