IMathAS-libretexts

Find the derivative.

$\displaystyle {y}=\frac{{{3}{x}-{4}}}{{{6}{x}+{1}}}$

$\displaystyle {3}{\left({6}{x}+{1}\right)}-{6}{\left({3}{x}-{4}\right)}$
$\displaystyle {6}{\left({3}{x}-{4}\right)}-{3}{\left({6}{x}+{1}\right)}$
$\displaystyle \frac{{{3}{\left({3}{x}-{4}\right)}-{6}{\left({6}{x}+{1}\right)}}}{{\left({6}{x}+{1}\right)}^{{2}}}$
$\displaystyle \frac{{{6}{\left({3}{x}-{4}\right)}-{3}{\left({6}{x}+{1}\right)}}}{{\left({6}{x}+{1}\right)}^{{2}}}$
$\displaystyle \frac{{{3}{\left({6}{x}+{1}\right)}+{6}{\left({3}{x}-{4}\right)}}}{{\left({6}{x}+{1}\right)}^{{2}}}$
$\displaystyle \frac{{{3}{\left({6}{x}+{1}\right)}-{6}{\left({3}{x}-{4}\right)}}}{{\left({6}{x}+{1}\right)}^{{2}}}$
$\displaystyle \frac{{1}}{{2}}$
$\displaystyle {3}{\left({6}{x}+{1}\right)}+{6}{\left({3}{x}-{4}\right)}$