Given the function
f
(
x
)
=
{
3
x
−
6
x
<
0
3
x
−
12
x
≥
0
\displaystyle {f{{\left({x}\right)}}}={\left\lbrace\begin{array}{cc} {3}{x}-{6}&{x}<{0}\\{3}{x}-{12}&{x}\geq{0}\end{array}\right.}
f
(
x
)
=
{
3
x
−
6
3
x
−
12
x
<
0
x
≥
0
Calculate the following values:
f
(
−
1
)
=
\displaystyle {f{{\left(-{1}\right)}}}=
f
(
−
1
)
=
f
(
0
)
=
\displaystyle {f{{\left({0}\right)}}}=
f
(
0
)
=
f
(
2
)
=
\displaystyle {f{{\left({2}\right)}}}=
f
(
2
)
=
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