A recent national report states the marital status distribution of the male population age 18 or older is as follows: Never Married (31.2%), Married (55%), Widowed (2.9%), Divorced (10.9%). The table below shows the results of a random sample of 930 adult men from California. Test the claim that the claim that the marital status distribution of the male population age 18 or older is different from the recent national report at the significant level of $\displaystyle \alpha$ = 0.1.

For this study, we should use Select an answer 1-PropZTest ANOVA 2-PropZInt χ²-Test 2-SampTInt 1-PropZInt TInterval 2-PropZTest 2-SampTTest χ²GOF-Test T-Test

Your friend Tiva helped you with the null and alternative hypotheses...
$\displaystyle {H}_{{0}}:$ The proportions are consistent with the national report.
$\displaystyle {H}_{{1}}:$ At least one of the proportion is different from the national report.

Outcome	Observed Frequency	Expected Frequency (Round to 3 decimal places)
Never Married	288
Married	506
Widowed	24
Divorced	112

The degree of freedom =
The test-statistic for this data = (Please show your answer to three decimal places.)

The p-value for this sample = (Please show your answer to four decimal places.)

The p-value is Select an answer less than (or equal to) alpha greater than alpha $\displaystyle \alpha$

Base on this, we should Select an answer accept the alternative reject the null fail to reject the null accept the null hypothesis

As such, the final conclusion is that...