Suppose the units of
f
(
x
)
\displaystyle {f{{\left({x}\right)}}}
f
(
x
)
are
gallons
day
\displaystyle \frac{\text{gallons}}{\text{day}}
day
gallons
, when
x
\displaystyle {x}
x
is measured in days.
The units of
f
′
(
x
)
\displaystyle {f}'{\left({x}\right)}
f
′
(
x
)
will be
gallons
⋅
\displaystyle \cdot
⋅
days
gallons
gallons
2
\displaystyle \text{gallons}^{{2}}
gallons
2
gallons
day
\displaystyle \frac{\text{gallons}}{\text{day}}
day
gallons
gallons
day
2
\displaystyle \frac{\text{gallons}}{\text{day}^{{2}}}
day
2
gallons
gallons
2
day
\displaystyle \frac{\text{gallons}^{{2}}}{\text{day}}
day
gallons
2
gallons
2
day
2
\displaystyle \frac{\text{gallons}^{{2}}}{\text{day}^{{2}}}
day
2
gallons
2
And the units of
∫
f
(
x
)
d
x
\displaystyle \int{f{{\left({x}\right)}}}\ {\left.{d}{x}\right.}
∫
f
(
x
)
d
x
will be
gallons
⋅
\displaystyle \cdot
⋅
days
gallons
gallons
2
\displaystyle \text{gallons}^{{2}}
gallons
2
gallons
day
\displaystyle \frac{\text{gallons}}{\text{day}}
day
gallons
gallons
day
2
\displaystyle \frac{\text{gallons}}{\text{day}^{{2}}}
day
2
gallons
gallons
2
day
\displaystyle \frac{\text{gallons}^{{2}}}{\text{day}}
day
gallons
2
gallons
2
day
2
\displaystyle \frac{\text{gallons}^{{2}}}{\text{day}^{{2}}}
day
2
gallons
2
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