IMathAS-libretexts

Find $\displaystyle \frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{x}\right.}}}$ given $\displaystyle {6}{y}^{{2}}+{8}{x}^{{2}}={8}$

$\displaystyle \frac{{8}}{{{12}{y}+{16}{x}}}$
$\displaystyle \frac{{{8}-{16}{x}}}{{{12}{y}}}$
$\displaystyle \frac{{-{4}{x}}}{{3}}$
$\displaystyle -\frac{{4}}{{3}}\frac{{x}}{{y}}$
$\displaystyle {0}$