If s\displaystyle {s}s is a distance given by s(t)=2t8+t6+6t\displaystyle {s}{\left({t}\right)}={2}{t}^{{8}}+{t}^{{6}}+{6}{t}s(t)=2t8+t6+6t , find the acceleration, a(t)\displaystyle {a}{\left({t}\right)}a(t) .
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