Let
d
y
d
t
=
2
t
−
y
+
1
\displaystyle \frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{t}\right.}}}={2}{t}-{y}+{1}
d
t
d
y
=
2
t
−
y
+
1
. Which of the following shows the nullcline and direction field for
d
y
d
t
\displaystyle \frac{{{\left.{d}{y}\right.}}}{{{\left.{d}{t}\right.}}}
d
t
d
y
?
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