In a random sample of 358 people that were tested for the Norcovirus, it was found that 290 did not have the virus. Construct a 92% confidence interval to estimate the proportion of the population that does not have the Norcovirus.

1. Which parameter are you estimating?
   Select an answer p p̂ x̄ s μ σ σ² s²
   
   
2. What is the point estimate?
   Select an answer p p̂ x̄ s μ σ σ² s² =
   
   
3. Check all of the requirements that are satisfied.
   
   • random
   • the $\displaystyle \overline{{{x}}}$ distribution is normal since $\displaystyle {n}\ge{30}$
   • the $\displaystyle \overline{{{x}}}$ distribution is normal since the $\displaystyle {x}$ distribution is normal
   • the $\displaystyle \hat{{{p}}}$ distribution is normal since $\displaystyle {n}\hat{{{p}}}\ge{10}$ and $\displaystyle {n}\hat{{{q}}}\ge{10}$
   
   
   
4. Which calculator function should you use?
   Select an answer 1-PropZInt 1-PropZTest ZInterval Z-Test TInterval T-Test invNorm
   
   
5. Find the margin of error. Round your answer to two decimal places.
   $\displaystyle {E}=$
   
   
6. Give the confidence interval in interval notation. Use decimals, not percentages.
   Preview Question 6 Part 7 of 8  
   
   
7. Select the correct conclusion.
   
   • We are 92% confident that the proportion of people in the sample that tested postitive for the Norcovirus is between the two proportions found.
   • We are 92% confident that the proportion of people in the sample that tested negative for the Norcovirus is between the two proportions found.
   • We are 92% confident that the proportion of the population that have the Norcovirus is between the two proportions found.
   • We are 92% confident that the proportion of the population that does not have the Norcovirus is between the two proportions found.