Find the first derivative of
g
(
x
)
=
−
6
ln
(
x
)
cos
(
x
6
)
\displaystyle {g{{\left({x}\right)}}}=-{6}{\ln{{\left({x}\right)}}}{\cos{{\left({x}^{{6}}\right)}}}
g
(
x
)
=
−
6
ln
(
x
)
cos
(
x
6
)
.
g
′
(
x
)
=
\displaystyle {g}'{\left({x}\right)}=
g
′
(
x
)
=
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