Find the first derivative of
z
=
tan
(
cos
9
(
t
)
)
\displaystyle {z}={\tan{{\left({{\cos}^{{9}}{\left({t}\right)}}\right)}}}
z
=
tan
(
cos
9
(
t
)
)
.
d
z
d
t
=
\displaystyle \frac{{\left.{d}{z}\right.}}{{\left.{d}{t}\right.}}=
d
t
d
z
=
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