A pharmaceutical company is about to launch a new manufacturing process in addition to the existing one. The quality control manager believes that the new method results in a different variation in the weights of the capsules. To verify the claim, the samples from each production line were obtained and the results are below (in mg):

Production Line 1:

100.598.6101.3103.695.7
103.3102.999.699.9100.8
104.9101.6101.1101.696.5

(Note: The average and the standard deviation of the data are respectively 100.8 mg and 2.52 mg.)

Production Line 2:

99.997.9100.397.9101.5
97.497.4100.396.4101
98.698.7

(Note: The average and the standard deviation of the data are respectively 98.9 mg and 1.62 mg.)

Use a 10% significance level to test the claim that the standard deviation of the capsule weights in the production line 1 is greater than the standard deviation of the capsule weights in the production line 2.

Procedure:

Assumptions: (select everything that applies)

Step 1. Hypotheses Set-Up:

H0:\displaystyle {H}_{{0}}: = , where the and the units are
 Ha:\displaystyle {H}_{{a}}:  , and the test is

Step 2. The significance level α=\displaystyle \alpha= %

Step 3. Compute the value of the test statistic: = (Round the answer to 3 decimal places)

Step 4. Testing Procedure: (Round the answers to 3 decimal places)

CVA PVA
Provide the critical value(s) for the Rejection Region: Compute the P-value of the test statistic:
left CV is and right CV is P-value is

Step 5. Decision:

CVA PVA
Is the test statistic in the rejection region? Is the P-value less than the significance level?

Conclusion:

Step 6. Interpretation:

At 10% significance level we have sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.