Find the first derivative of
g
(
x
)
=
(
16
x
12
+
7
)
5
\displaystyle {g{{\left({x}\right)}}}={\left({16}{x}^{{12}}+{7}\right)}^{{5}}
g
(
x
)
=
(
16
x
12
+
7
)
5
.
g
′
(
x
)
=
\displaystyle {g}'{\left({x}\right)}=
g
′
(
x
)
=
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