Find the first derivative of
g
(
x
)
=
(
−
11
x
10
−
8
)
6
\displaystyle {g{{\left({x}\right)}}}={\left(-{11}{x}^{{10}}-{8}\right)}^{{6}}
g
(
x
)
=
(
−
11
x
10
−
8
)
6
.
g
′
(
x
)
=
\displaystyle {g}'{\left({x}\right)}=
g
′
(
x
)
=
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