When integrating
∫
x
−
6
x
+
3
d
x
\displaystyle \int{x}\sqrt{{-{6}{x}+{3}}}{\left.{d}{x}\right.}
∫
x
−
6
x
+
3
d
x
, we can use the substitution
u
=
−
6
x
+
3
\displaystyle {u}=-{6}{x}+{3}
u
=
−
6
x
+
3
. What will the resulting integral be after the substitution?
∫
\displaystyle \int
∫
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Question 6
d
u
\displaystyle {d}{u}
d
u
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