When integrating x4x+3dx\displaystyle \int\frac{{x}}{{{4}{x}+{3}}}{\left.{d}{x}\right.}, we can use the substitution u=4x+3\displaystyle {u}={4}{x}+{3}. What will the resulting integral be after the substitution?

\displaystyle \int   du\displaystyle {d}{u}