When integrating ∫ln⁡(x)x−2\displaystyle \int{\ln{{\left({x}\right)}}}{x}^{{-{{2}}}}dx\displaystyle {\left.{d}{x}\right.} by parts, we can begin by letting u=ln⁡(x)\displaystyle {u}={\ln{{\left({x}\right)}}}. Complete the rest of the parts for this integral.

dv=\displaystyle {d}{v}=   dx\displaystyle {\left.{d}{x}\right.}

du=\displaystyle {d}{u}=   dx\displaystyle {\left.{d}{x}\right.}

v=\displaystyle {v}=  

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