A dean wants to check the consistency of teaching quality among the faculty in one of the departments. A sample of students was obtained from three classes taught by three different faculty, and their common final exam scores were recorded.
Classes | Final Exam Scores | ||||||||||
Class 1 |
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Class 2 |
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Class 3 |
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Class 4 |
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Class 5 |
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Procedure:
Assumptions: (select everything that applies)
Step 1. Hypotheses Set-Up:
, and the test is |
Step 2. The significance level %
Step 3. With the total number of observations, n=, and the number of populations, k=, compute the value of the test statistic using the table below:
Source | DF | SS | MS | F | P |
Duration | k-1= | 294.1416 | 73.5354 | 0.851 | 0.502 |
Error | n-k= | 3455.1 | 86.3775 | ||
Total | 44 | 3749.2416 |
The test statistic is = (Round the answer to 3 decimal places)
with the degrees of freedom (dfn=,dfd=)
Step 4. Testing Procedure: (Round the answers to 3 decimal places)
CVA | PVA |
Provide the critical value(s) for the Rejection Region: | Compute the P-value of the test statistic: |
left CV is and right CV is | P-value is |
Step 5. Decision:
CVA | PVA |
Is the test statistic in the rejection region? | Is the P-value less than the significance level? |
Conclusion:
Step 6. Interpretation:
At 10% significance level we have sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.
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