Evaluate ∫xsec2x\displaystyle \int{x}{{\sec}^{{2}}{x}}∫xsec2x dx\displaystyle {\left.{d}{x}\right.}dx. Show your work below.
∫xsec2x\displaystyle \int{x}{{\sec}^{{2}}{x}}∫xsec2x dx=\displaystyle {\left.{d}{x}\right.}=dx=+C Preview Question 6 Part 2 of 2
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