Find the general solution to the equation below. Use
t
\displaystyle {t}
t
for the independent variable and
c
1
,
c
2
\displaystyle {c}_{{1}},{c}_{{2}}
c
1
,
c
2
for arbitrary constants.
5
y
′
′
+
40
y
′
+
125
y
=
0
\displaystyle {5}{y}{''}+{40}{y}'+{125}{y}={0}
5
y
′′
+
40
y
′
+
125
y
=
0
y
=
\displaystyle {y}=
y
=
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