Solve the ODE below for the given initial conditions using undetermined coefficients. Use
x
\displaystyle {x}
x
as the independent variable.
y
′
′
+
4
y
′
+
4
y
=
4
t
+
9
\displaystyle {y}{''}+{4}{y}'+{4}{y}={4}{t}+{9}
y
′′
+
4
y
′
+
4
y
=
4
t
+
9
y
(
0
)
=
29
4
,
y
′
(
0
)
=
−
11
\displaystyle {y}{\left({0}\right)}=\frac{{29}}{{4}},\quad{y}'{\left({0}\right)}=-{11}
y
(
0
)
=
4
29
,
y
′
(
0
)
=
−
11
y
(
x
)
=
\displaystyle {y}{\left({x}\right)}=
y
(
x
)
=
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