Find an antiderivative F(x)\displaystyle {F}{\left({x}\right)} of the function f(x)=−3x+2\displaystyle {f{{\left({x}\right)}}}=-{3}\sqrt{{{x}}}+{2} such that F(0)=−11\displaystyle {F}{\left({0}\right)}=-{11}.

F(x)=\displaystyle {F}{\left({x}\right)}=  

Now, find a different antiderivative G(x)\displaystyle {G}{\left({x}\right)} of the function f(x)=−3x+2\displaystyle {f{{\left({x}\right)}}}=-{3}\sqrt{{{x}}}+{2} such that G(0)=−8\displaystyle {G}{\left({0}\right)}=-{8}.

G(x)=\displaystyle {G}{\left({x}\right)}=  

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