Find an antiderivative $\displaystyle {F}{\left({x}\right)}$ of the function $\displaystyle {f{{\left({x}\right)}}}={5}{x}^{{2}}-{6}{x}+{3}$ such that $\displaystyle {F}{\left({1}\right)}={7}$.

$\displaystyle {F}{\left({x}\right)}=$Preview Question 6 Part 1 of 2  

(Hint: Write the constant term on the end of the antiderivative as $\displaystyle {C}$, and then set $\displaystyle {F}{\left({1}\right)}={7}$ and solve for $\displaystyle {C}$.)

Now, find a different antiderivative $\displaystyle {G}{\left({x}\right)}$ of the function $\displaystyle {f{{\left({x}\right)}}}={5}{x}^{{2}}-{6}{x}+{3}$ such that $\displaystyle {G}{\left({1}\right)}={10}$.

$\displaystyle {G}{\left({x}\right)}=$Preview Question 6 Part 2 of 2