For the integral 47e6x5dx\displaystyle {\int_{{{4}}}^{{{7}}}}{e}^{{{6}{x}-{5}}}{\left.{d}{x}\right.}, if we use the substitution u=6x5\displaystyle {u}={6}{x}-{5}, what will be the new integral?

ab\displaystyle {\int_{{a}}^{{b}}}   du\displaystyle {d}{u}

Where a=\displaystyle {a}=  

And b=\displaystyle {b}=