Which of these could be viewed as the
outside
function in the composition function
y
=
5
x
2
+
1
\displaystyle {y}={\frac{{{5}}}{{{x}^{{2}}+{1}}}}
y
=
x
2
+
1
5
?
1
x
2
+
1
\displaystyle {\frac{{{1}}}{{{x}^{{2}}+{1}}}}
x
2
+
1
1
x
2
+
1
\displaystyle {x}^{{2}}+{1}
x
2
+
1
1
x
\displaystyle {\frac{{{1}}}{{{x}}}}
x
1
5
\displaystyle {5}
5
5
x
\displaystyle {\frac{{{5}}}{{{x}}}}
x
5
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