Given the function P(x)=(x3)(x+4)\displaystyle {P}{\left({x}\right)}={\left({x}-{3}\right)}{\left({x}+{4}\right)}, find
its y\displaystyle {y}-intercept is

 


its x\displaystyle {x}-intercepts are

x1=\displaystyle {x}_{{1}}=   and

x2=\displaystyle {x}_{{2}}=   with x1x2\displaystyle {x}_{{1}}\le{x}_{{2}}


When x\displaystyle {x}\to-\infty, y\displaystyle {y}\to \displaystyle  (up or down)
When x\displaystyle {x}\to\infty, y\displaystyle {y}\to \displaystyle (up or down)