Let f(x)=9ln(secx+tanx)\displaystyle {f{{\left({x}\right)}}}={9}{\ln{{\left({\sec{{x}}}+{\tan{{x}}}\right)}}}f(x)=9ln(secx+tanx) f′′(x)=\displaystyle {f}{''}{\left({x}\right)}=f′′(x)= Preview Question 6 HINT: Simplify the first derivative before you find the second derivative.
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