Given the function: f(x)=2x2+9x1\displaystyle {f{{\left({x}\right)}}}={2}{x}^{{2}}+{9}{x}-{1}. Calculate the following values:

a) f(0)=\displaystyle {f{{\left({0}\right)}}}=  
b) f(2)=\displaystyle {f{{\left({2}\right)}}}=  
c) f(3)=\displaystyle {f{{\left(-{3}\right)}}}=  
d) f(h)=\displaystyle {f{{\left({h}\right)}}}=  
e) f(t+1)=\displaystyle {f{{\left({t}+{1}\right)}}}=  
f) f(2x)=\displaystyle {f{{\left(-{2}{x}\right)}}}=