Hint 1 Hint 2

For vectors B⃗=−3x^−6y^\displaystyle \vec{{B}}=-{3}\hat{{x}}-{6}\hat{{y}} and A⃗=−6x^−3y^\displaystyle \vec{{A}}=-{6}\hat{{x}}-{3}\hat{{y}} calculate:

  1.  A⃗+B⃗=\displaystyle \vec{{A}}+\vec{{B}}=  x^+\displaystyle \hat{{x}}+  y^\displaystyle \hat{{y}} 
                                 
    ∣A⃗+B⃗∣=\displaystyle {\left|\vec{{A}}+\vec{{B}}\right|}= 
    Direction in degrees (between 0° and 360°) relative to +x−\displaystyle +{x}-axis:
  2.  A⃗−B⃗=\displaystyle \vec{{A}}-\vec{{B}}=  x^+\displaystyle \hat{{x}}+  y^\displaystyle \hat{{y}} 
                                  
    ∣A⃗−B⃗∣=\displaystyle {\left|\vec{{A}}-\vec{{B}}\right|}= 
    Direction in degrees (between 0° and 360°) relative to +x−\displaystyle +{x}-axis:

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