For the standard normal variable Z\displaystyle {Z}Z , find the probability P(2.55<Z<3.13)\displaystyle {P}{\left({2.55}<{Z}<{3.13}\right)}P(2.55<Z<3.13) :
P(2.55<Z<3.13)=\displaystyle {P}{\left({2.55}<{Z}<{3.13}\right)}=P(2.55<Z<3.13)= (Round the answer to 4 decimal places)
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