For a normal variable $\displaystyle {X}\sim{N}{\left(\mu={29.2},\sigma={6.94}\right)}$, find $\displaystyle {x}_{{0.01}}$, the value that divides the area under the density curve into 0.99 to the left and 0.01 to the right.

$\displaystyle {x}_{{0.01}}=$  (Round the answer to 2 decimal places)