Given α=0.07\displaystyle \alpha={0.07}α=0.07, zα/2=z0.035=1.81\displaystyle {z}_{{\alpha/{2}}}={z}_{{0.035}}={1.81}zα/2=z0.035=1.81, p^i=0.79\displaystyle \hat{{{p}}}_{{i}}={0.79}p^i=0.79, and n=120\displaystyle {n}={120}n=120 compute the margin of error using the formula
ME=zα/2p^i(1−p^i)n=\displaystyle {M}{E}={z}_{{\alpha/{2}}}\sqrt{{\frac{{\hat{{{p}}}_{{i}}{\left({1}-\hat{{{p}}}_{{i}}\right)}}}{{n}}}}=ME=zα/2np^i(1−p^i)= (Round the answer to 4 decimal places.)
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