Let $\displaystyle {Y}\sim{B}{\left({n}={2},{p}={0.2}\right)}$ with the following probability distribution table:

$\displaystyle {k}$	$\displaystyle {P}{\left({Y}={k}\right)}={{C}_{{k}}^{{n}}}{p}^{{k}}{\left({1}-{p}\right)}^{{{n}-{k}}}$
0	$\displaystyle {P}{\left({Y}={0}\right)}=$ 0.64
1	$\displaystyle {P}{\left({Y}={1}\right)}=$ 0.32
2	$\displaystyle {P}{\left({Y}={2}\right)}=$ 0.04

Use the probability distribution table to find the following:

1.  $\displaystyle {P}{\left({Y}\lt-{2}\right)}=$
2.  $\displaystyle {P}{\left({Y}\le{3}\right)}=$
3.  $\displaystyle {P}{\left({Y}\le{1}\right)}=$